2x^2+5x-3=(2x+1)(x-3)

Solution for 2x^2+5x-3=(2x+1)(x-3) equation:

2x^2+5x-3=(2x+1)(x-3)

We move all terms to the left:

2x^2+5x-3-((2x+1)(x-3))=0

We multiply parentheses ..

2x^2-((+2x^2-6x+x-3))+5x-3=0


We calculate terms in parentheses: -((+2x^2-6x+x-3)), so:

(+2x^2-6x+x-3)

We get rid of parentheses

2x^2-6x+x-3

We add all the numbers together, and all the variables

2x^2-5x-3

Back to the equation:

-(2x^2-5x-3)


We add all the numbers together, and all the variables

2x^2+5x-(2x^2-5x-3)-3=0

We get rid of parentheses

2x^2-2x^2+5x+5x+3-3=0

We add all the numbers together, and all the variables

10x=0

x=0/10

x=0